SOLUTION: Two wagons travel towards each other leaving at the same time from cities located 48 miles apart. One wagon travels at the average speed of 12 miles per hour faster than the other

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Question 535392: Two wagons travel towards each other leaving at the same time from cities located 48 miles apart. One wagon travels at the average speed of 12 miles per hour faster than the other wagon. What are the average speeds of the wagons if they pass each other in 2 hours?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let s = the speed of the slower wagon
+s+%2B+12+ = the speed of the faster wagon
Think of one wagon be stationary and the
other moving at the sum of their speeds
+48+=+%28+s+%2B+s+%2B+12+%29%2A2+
+48+=+4s+%2B+24+
+4s+=+24+%7D%7D%0D%0A%7B%7B%7B+s+=+6+
+s+%2B+12+=+18+
Their speeds are 6 mi/hr and 18 mi/hr
check:
slower wagon:
+d%5B1%5D+=+6%2A2+
+d%5B1%5D+=+12+ mi
faster wagon:
+d%5B2%5D+=+18%2A2+
+d%5B2%5D+=+36+
+d%5B1%5D+%2B+d%5B2%5D+=+48+
OK