SOLUTION: i have to find a quadratic function in standard form for these set of points (-1,2),(0,1),(1,-4) i dont get how to though

Algebra ->  Rational-functions -> SOLUTION: i have to find a quadratic function in standard form for these set of points (-1,2),(0,1),(1,-4) i dont get how to though      Log On


   

Question 535263: i have to find a quadratic function in standard form for these set of points (-1,2),(0,1),(1,-4)
i dont get how to though
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
y = ax^2 + bx + c ___ plug the points into the general equation
___ then solve the resulting linear system for the coefficients (a, b, c)

2 = a(-1)^2 + b(-1) + c ___ 2 = a - b + c

1 = a(0)^2 + b(0) + c ___ 1 = c

-4 = a(1)^2 + b(1) + c ___ -4 = a + b + c