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Point slope form is y-y1 = m (x-x1): Keep in mind y1 and x1 mean y sub 1 and x sub 1, the y and x-coordinate for the point you'll use.
x1 = -3 and y1=4 and m 7/2
y-4=(7/2)(x+3) (x-(-3) = x+3).
For the second problem remember the slope-intercept equation is y=mx+b where m is the slope and b is the y-intercept (y when x=0).
We need a slope, and one point to find the equation. We'll use one point and the slope to find the b value. First we have to find the slope which is
Difference in y divided by difference in x
(y-y1) / (x-x1) It doesn't matter which point we choose as (x,y) and which as (x1,y1).
We'll use (-2,0) as (x,y) and (0,3) as (x1,y1)
slope=m=(0-3)/(-2-0) = -3/-2 = 3/2.
Plug that slope and the values for either point into y=mx+b to find b. We'll use (-2,0)
0=(3/2)(-2)+b ---> 0 = -3 + b (add 3 to both sides) 3=b.
We have b=3 and m = 3/2, so the slope-intercept equation y=mx+b is:
y = (3/2)x + 3
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