Question 535087: Find a quadratic function in standard form for each set of points.
(0, 3), (1, –4), (2, –9)
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! Standard form: y = ax^2 + bx + c
Use the given points to solve for a, b c
The point (0,3) gives c = 3 since the a and b terms are zero.
Substituting the other two pairs of points gives
-4 = a + b + 3
-9 = 4a + 2b + 3
Solving these two equations gives a = 1, b = -8
So the function is
y = f(x) = x^2 - 8x + 3
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