Question 53497: A food chemist test enzymes for their ability to break down pectin in fruit juices. Excess pectin makes juice cloudy. In one test, the chemist measures the concentration of the enzyme, C, in milligrams per milliliter and the fraction of light absorbed by the liquid, a.
if A is greater than 0.07c + 0.02, then the enzyme is working as it should. Graph the inequality in the first quadrant
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! if A is greater than 0.07c + 0.02, then the enzyme is working as it should. Graph the inequality in the first quadrant.
------------
A>=0.07C + 0.02
Draw a coordinate system with C as the horizontal axis
and A as the vertical axis.
--------
Generate and plot two points as follows:
If C=0, A=0.02 giving you the point (0,0.02)
If A=0,C=10 A= 0.72 giving you the point (10,0.72)
-------
Draw a line (only in the 1st quadrant)
That is the graph of the equality.
----
To add the graph of the inequality shade the area above the line
but staying in the 1st quadrant.
Cheers,
Stan H.
|
|
|