SOLUTION: Lauren is jogging to the store at 10 mph. She gets what she needs and returns home at 5 mph. Her total jogging time was one hour. How far is the store from her house? I need a

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Lauren is jogging to the store at 10 mph. She gets what she needs and returns home at 5 mph. Her total jogging time was one hour. How far is the store from her house? I need a      Log On

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Question 534314: Lauren is jogging to the store at 10 mph. She gets what she needs and returns home at 5 mph. Her total jogging time was one hour. How far is the store from her house?

I need an equation...I don't understand how to do this...
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+%7D%7D%5D+=+distance+from+store+to+house+in+miles%0D%0ALet+%7B%7B%7B+t+ = time to go from house to store in hrs
+1+-+t+ = time to go from store to house in hrs
--------
House to store:
(1) +d+=+10t+
Store to house:
(2) +d+=+5%2A%28+1+-+t+%29+
---------------
Substitute (1) into (2)
(2) +10t+=+5%2A%28+1+-+t+%29+
(2) +10t+=+5+-+5t+
(2) +15t+=+5+
(2) +t+=+5%2F15+
(2) +t+=+1%2F3+ hr
and, from (1):
(1) +d+=+10t+
(1) +d+=+10%2F3+
The distance from store to house is 3.333 mi
check:
(2) +d+=+5%2A%28+1+-+t+%29+
(2) +10%2F3+=+5%2A%282%2F3%29+
(2) +10%2F3+=+10%2F3+
and
(1) +d+=+10t+
(1) +10%2F3+=+10%2A%281%2F3%29+
(1) +10%2F3+=+10%2F3+
OK