SOLUTION: At 3:00 p.m., Catanya and Chad had already made 46 candles. By 5:00 p.m., the total reached 100 candles. Assuming a constant production rate, at what time did they make their 82nd

Algebra ->  Rate-of-work-word-problems -> SOLUTION: At 3:00 p.m., Catanya and Chad had already made 46 candles. By 5:00 p.m., the total reached 100 candles. Assuming a constant production rate, at what time did they make their 82nd       Log On


   

Question 534079: At 3:00 p.m., Catanya and Chad had already made 46 candles. By 5:00 p.m., the total reached 100 candles. Assuming a constant production rate, at what time did they make their 82nd candle?

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
If not studying linear functions, the problem can be visualized and solved easily:
In 2 hours (between 3:00 PM and 5:00 PM) they made 54 candles.
100-46=54
Assuming a constant production rate, that's 27 candles per hour.
By the time they finish their 81st candle the number of candles made after 3:00 PM will be
81-54=27
and the required time to make those 27 candles would be exactly one hour, so one hour after 3:00 PM (at 4:00 PM) they would have made 81 candles.
Assuming a constant production rate, 27 candles in 60 minutes means the time (in minutes) required to make one candle is
60%2F27=20%2F9
That's a little more than 2 minutes.
So at 4:00 PM they would start working on that 82nd candle and they would be done (and already working on the next one) by 4:03 PM.
If already studying linear functions, you would make it complicated. You would think of the number of candles as a function of time, write it as a function, talk about its slope and intercepts (maybe even graph it), set up a linear equation and solve it. If that's what you are expected to do (hopefully it's not), we could show you how. Just ask.