SOLUTION: Ricardo Guiterrez has a box of coins that he uses to play poker with friends. The box currently contains 38 coins, consisting of quarters, dimes and pennies. The number of pennie

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Ricardo Guiterrez has a box of coins that he uses to play poker with friends. The box currently contains 38 coins, consisting of quarters, dimes and pennies. The number of pennie      Log On

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Question 533991: Ricardo Guiterrez has a box of coins that he uses to play poker with friends. The box currently contains 38 coins, consisting of quarters, dimes and pennies. The number of pennies is equal to the number of dimes and the total value is $4.04. How many of each denomination of coin does Ricardo have?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let p = number of pennies
Let d = number of dimes
Let q = number of quarters
given:
(1) +p+%2B+d+%2B+q+=+38+
(2) +p+=+d+
(3) +p+%2B+10d+%2B+25q+=+404+ ( in cents )
----------------------
First substitute (2) into (1)
(1) +d+%2B+d+%2B+q+=+38+
(1) +q+=+38+-+2d+
Now substitute (1) and (2) into (3)
(3) +d+%2B+10d+%2B+25%2A%28+38+-+2d+%29+=+404+
(3) +11d+%2B+950+-+50d+=+404+
(3) +-39d+=+-950+%2B+404+
(3) +-39d+=+-546+
(3) +d+=+14+
and, since
(2) +p+=+d+
(2) +p+=+14+
and
(1) +q+=+38+-+2d+
(1) +q+=+38+-+28+
(1) +q+=+10+
Ricardo has 14 pennies, 14 dimes, and 10 quarters
check:
(3) +p+%2B+10d+%2B+25q+=+404+
(3) +14+%2B+10%2A14+%2B+25%2A10+=+404+
(3) +14+%2B+140+%2B+250+=+404+
(3) +404+=+404+
OK