Question 53397: Complete the ordered pairs so that each is a solution for the given equation.
3x+4y=12 (0, ), ( ,3/4), ( ,0), (8/3, )
McGraw Hill 6th edition, chapter 6, section 1, problem # 24. Thanks for your help!!
Found 2 solutions by funmath, venugopalramana:
Answer by funmath(2933)   (Show Source):
You can put this solution on YOUR website! Since you catagorized this as graphing, I will talk you trhough that as well.
3x+4y=12
For (0,) think of it as (0,y). Substitute 0 in for x and sole for y:
3(0)+4y=12
0+4y=12
4y=12
y=3
Plot (0,3)
---------------
For (,3/4) think of that as (x,3/4), substitute 3/4 in for y and solve for x:
3x+3-3=12-3
3x=9
x=3
Plot (3,3/4)
-------------------
For (,0) think of it as (x,0). Substitute 0 in for y and solve for x.
3x+4(0)=12
3x+0=12
3x=12
x=4
Plot (4,0)
-------------------
For (8/3,) think of it as (8/3,y). Substitute 8/3 for x and solve for y.
-8+8+4y=12-8
4y=4
y=1
Plot (8/3,1)
Connect all your dots and you have:
Happy Calculating!!!
Answer by venugopalramana(3286)  (Show Source):
You can put this solution on YOUR website! Complete the ordered pairs so that each is a solution for the given equation.
3x+4y=12
(0, ),
3*0+4Y=12.....Y=3
(0,3)
( ,3/4),
3X+4*3/4=12.......
3X=9
X=3
(3,3/4)
( ,0),
3X+4*0=12
X=4
(4,0)
(8/3, )
3*8/3+4Y=12
4Y=12-8=4
Y=1
(8/3,1)
McGraw Hill 6th edition, chapter 6, section 1, problem # 24. Thanks for your help!!
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