SOLUTION: You have nine people. Each day these nine people must break up into 3 groups of three. How many days can they meet without the same three people meeting again in any group of thr

Algebra ->  Permutations -> SOLUTION: You have nine people. Each day these nine people must break up into 3 groups of three. How many days can they meet without the same three people meeting again in any group of thr      Log On


   

Question 533454: You have nine people. Each day these nine people must break up into 3 groups of three. How many days can they meet without the same three people meeting again in any group of three? Hope that was clear enough and help will be greatly appreciated.
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Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
there are 9C3 ways of selecting a group of 3 from 9 ___ 84 different groups

3 groups per day means 28 days (84 / 3) without repeating