SOLUTION: One-third of the sum of two consecutive integers is 6 less than the smaller integer. Find the integers.

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Question 53313: One-third of the sum of two consecutive integers is 6 less than the smaller integer. Find the integers.
Found 2 solutions by Nate, Earlsdon:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
first integer = i
second integer = i + 1
(1/3)(2i + 1) = i - 6
2i + 1 = 3i - 18
19 = i
first integer = 19
second integer = 20

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the smaller integer and x+1 = the next consecutive integer.
%28x%2Bx%2B1%29%2F3+=+x-6 Multiply both sides by 3 and simplify.
2x%2B1+=+3x-18 Subtract 2x from both sides.
1+=+x-18 Add 18 to both sides.
19+=+x
The two consecutive integers are: 19 and 20