SOLUTION: The length of a rectangle is 8 + the width. The area of the rectangle is <= 33. Find the width. I know (through trial and error) the answer is 3. I am trying to show my child ho

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 8 + the width. The area of the rectangle is <= 33. Find the width. I know (through trial and error) the answer is 3. I am trying to show my child ho      Log On


   

Question 533092: The length of a rectangle is 8 + the width. The area of the rectangle is <= 33. Find the width. I know (through trial and error) the answer is 3. I am trying to show my child how to solve the equation, (8+w)w<=33, but have no Idea how to do the work.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
w^2 + 8w - 33 ≤ 0

(w + 11)(w - 3) ≤ 0

the product must be ≤0, so w must be ≤3 AND ≥-11 ___ -11 ≤ w ≤ 3

negative (and zero) values are not realistic ___ 0 < w ≤ 3