You can put this solution on YOUR website! Please help, I'm confused on this problem.
log(base2)x = log(base4)(2x-1)
Solve for x.
**
log(base2)x = log(base4)(2x-1)
change to a common base(2)
log of the number with the new base(2) divided by log of the old base(4) with the new base(2).
log2(x)=log2(2x-1)/log2(4)
log2(4)=2
log2(x)=log2(2x-1)/2
2log2(x)-log2(2x-1)=0
log2(x^2)-log2(2x-1)=0
place under single log
log2[(x^2)/(2x-1)]=0
convert to exponential form: base(2) raised to log of number(0)=number(x^2)/(2x-1)
2^0=(x^2)/(2x-1)=1
x^2=2x-1
x^2-2x+1=0
(x-1)^2=0
x=1 (multiplicity 2)
(