SOLUTION: This is factoring perfect Square trinomials, this is the problem, m^2 - 2m + 1
We are to determine whether this is a perfect square. This is my answer: (m+1)(m+1) I know it's a pe
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-> SOLUTION: This is factoring perfect Square trinomials, this is the problem, m^2 - 2m + 1
We are to determine whether this is a perfect square. This is my answer: (m+1)(m+1) I know it's a pe
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Question 532685: This is factoring perfect Square trinomials, this is the problem, m^2 - 2m + 1
We are to determine whether this is a perfect square. This is my answer: (m+1)(m+1) I know it's a perfect square but I know this is not the right answer to it. Could you please show me step by step how to do this one please? Found 2 solutions by stanbon, lwsshak3:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! This is factoring perfect Square trinomials, this is the problem, m^2 - 2m + 1
We are to determine whether this is a perfect square. This is my answer: (m+1)(m+1) I know it's a perfect square but I know this is not the right answer to it. Could you please show me step by step how to do this one please?
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1st and 2rd terms are perfect squares.
Take the square root of each.
Use the sign of the middle term.
Ans (m-1)^2
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Cheers,
Stan H.
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You can put this solution on YOUR website! This is factoring perfect Square trinomials, this is the problem, m^2 - 2m + 1
We are to determine whether this is a perfect square. This is my answer: (m+1)(m+1) I know it's a perfect square but I know this is not the right answer to it. Could you please show me step by step how to do this one please?
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m^2 - 2m + 1
(m^2-2m+1)+1-1
The 1 inside the parenthesis came from taking half of the coefficient of the middle term(1), then squaring it (1^2)=1.
The (-1) outside the parenthesis was added in to balance the 1 we added inside the parenthesis.
(m^2-2m+1)+1-1
=(m^2-2m+1) which is a perfect square
factor: (m-1)^2
m comes from the sqrt of the first term and 1 comes from the sqrt of the last term of the perfect square. The negative sign always matches the sign of the middle term.
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