SOLUTION: Approximately 8% of people are left-handed. If two people are selected at random, what is the probability of the following events?
A. P(Both are right-handed) =
B. P(Both are
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-> SOLUTION: Approximately 8% of people are left-handed. If two people are selected at random, what is the probability of the following events?
A. P(Both are right-handed) =
B. P(Both are
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Question 532665: Approximately 8% of people are left-handed. If two people are selected at random, what is the probability of the following events?
A. P(Both are right-handed) =
B. P(Both are left-handed) =
C. P(One is right-handed and the other is left-handed) =
D. P(At least one is right-handed) = Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Approximately 8% of people are left-handed. If two people are selected at random, what is the probability of the following events?
A. P(Both are right-handed) = (0.92)^2
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B. P(Both are left-handed) = (0.08)^2
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C. P(One is right-handed and the other is left-handed) = 1 -[0.92^2+0.08^2]
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D. P(At least one is right-handed) = 1 - 0.08^2
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Cheers,
Stan H.
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