SOLUTION: the length of a rectangle is four times its width, the area is 144 yards squared what is the perimiter?

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Question 532492: the length of a rectangle is four times its width, the area is 144 yards squared what is the perimiter?
Answer by jkrsmsc76(5) About Me  (Show Source):
You can put this solution on YOUR website!
L = 4W (the length is 4 times the width
Area+=+L%2AW
so Area+=+4W%2AW
Since the Area is 144
144+=+4W%2AW or 144=4W%5E2
Divide both sides by 4 to get 36=W%5E2
Take the square root of both sides to get W=6+or+W=-6. Since it is a length, we don't need the negative, so W=6
If W=6 and the length is 4 times the width, L=4%2A6=24.
We now know the width is 6 and the length is 24, so we can find the perimeter, using the perimeter formula: P=2L%2B2W
So P=2%2824%29%2B2%286%29=48%2B12=60+yards