SOLUTION: Find the solutions of the equation that are in the interval [0, 2π). csc^5 theta = 4 csc theta I moved 4csc to the left side to get csc^5 theta - 4csc theta =0, then I fac

Algebra ->  Trigonometry-basics -> SOLUTION: Find the solutions of the equation that are in the interval [0, 2π). csc^5 theta = 4 csc theta I moved 4csc to the left side to get csc^5 theta - 4csc theta =0, then I fac      Log On


   

Question 532400: Find the solutions of the equation that are in the interval [0, 2π).
csc^5 theta = 4 csc theta
I moved 4csc to the left side to get csc^5 theta - 4csc theta =0, then I factored out csc to get csc(csc^4 theta -4)=0. I don't know where to get from there or if I was on the right track. Also I don't know when csc = 0. :( Please help.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the solutions of the equation that are in the interval [0, 2π).
csc^5 theta = 4 csc theta
I moved 4csc to the left side to get csc^5 theta - 4csc theta =0, then I factored out csc to get csc(csc^4 theta -4)=0. I don't know where to get from there or if I was on the right track. Also I don't know when csc = 0.
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csc is never 0, ignore that.
That leaves csc^4 = 4
sin^4 = 1/4
sin = +/- sqrt(2)/2
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I doubt you want the complex solutions.