SOLUTION: write the slope intercept form of the equation of the line described: (16, 2) perpindicular to y= -4x-9

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Question 532344: write the slope intercept form of the equation of the line described: (16, 2) perpindicular to y= -4x-9
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The equation for the line described is
y=-4x-9.
That equation is in the slope-intercept form, which looks like
y=mx%2Bb, where m is the slope of the line and b is the y-coordinate for the point where the line intercepts the y-axis, called the y-intercept, or (sometimes) just intercept, for short.
That means that the slope of the line described is m=-4.
When lines are perpendicular, their slopes multiply to give you -1,
meaning that the slope of the perpendicular line is
m=%28-1%29%2F%28-4%29=1%2F4
If that perpendicular line passes through the point (16,2) with
x=16 and y=2, you have enough information to find the equation for that perpendicular line.
Knowing that it's going to be
y=mx%2Bb=%281%2F4%29x%2Bb
you could substitute x=16 and y=2 to find b.
Otherwise, you could use the point-slope form of the equation, using the coordinates of the given point and the calculated slope to write the equation as
y-2=%281%2F4%29%2A%28x-16%29.
A little algebra transforms the equation above into the slope-intercept form for the perpendicular line.