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Question 531815: Find the vertex and focus of a parabola with the given equation.
y2-6y-12x+21=0
and also this equation
x2+4x-8y-4=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the vertex and focus of a parabola with the given equation.
y2-6y-12x+21=0
and also this equation
x2+4x-8y-4=0
**
y2-6y-12x+21=0
complete the square
(y^2-6y+9)=12x-21+9=12x-12=12(x-1)
(y-3)^2=12(x-1)
This is an equation of a parabola of standard form: (y-k)^2=4p(x-h), with (h,k) being the (x,y) coordinates of the vertex. Parabola opens rightwards.
For given equation:
vertex: (1,3)
4p=12
p=3
focus: (1+p,3)=(4,3) (p units from vertex on axis of symmetry)
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