SOLUTION: Can you help me find the Values for the variables for the problem: x^2 - 10x + 16 =0 ? thx :)

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Question 531609: Can you help me find the Values for the variables for the problem:
x^2 - 10x + 16 =0
? thx :)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E2-10x%2B16=0 Start with the given equation.


Notice that the quadratic x%5E2-10x%2B16 is in the form of Ax%5E2%2BBx%2BC where A=1, B=-10, and C=16


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-10%29+%2B-+sqrt%28+%28-10%29%5E2-4%281%29%2816%29+%29%29%2F%282%281%29%29 Plug in A=1, B=-10, and C=16


x+=+%2810+%2B-+sqrt%28+%28-10%29%5E2-4%281%29%2816%29+%29%29%2F%282%281%29%29 Negate -10 to get 10.


x+=+%2810+%2B-+sqrt%28+100-4%281%29%2816%29+%29%29%2F%282%281%29%29 Square -10 to get 100.


x+=+%2810+%2B-+sqrt%28+100-64+%29%29%2F%282%281%29%29 Multiply 4%281%29%2816%29 to get 64


x+=+%2810+%2B-+sqrt%28+36+%29%29%2F%282%281%29%29 Subtract 64 from 100 to get 36


x+=+%2810+%2B-+sqrt%28+36+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%2810+%2B-+6%29%2F%282%29 Take the square root of 36 to get 6.


x+=+%2810+%2B+6%29%2F%282%29 or x+=+%2810+-+6%29%2F%282%29 Break up the expression.


x+=+%2816%29%2F%282%29 or x+=++%284%29%2F%282%29 Combine like terms.


x+=+8 or x+=+2 Simplify.


So the solutions are x+=+8 or x+=+2