You can put this solution on YOUR website! y = (x+5)^2 + 5
y = x^2 +10x +25 +5
y = x^2 +10x +30
.
You know this is a parabola. So find several values of x to calculate values of y.
.
The axis of symmetry is where x = -b/2a.
-10/2 = -5
.
The vertex is where the parabola ends. It occurs on the axis of symmetry.
y = (-5)^2 +10(-5) + 30
y = 25 -50 + 30
y = 5
.
Pick several points to either side of the vertex.
x = -4, y = 6
x = -6, y = 6
x = 0, y = 30
x = -10, y = 30
x = 5, y = 105
x = -15, y = 105
.
(