SOLUTION: A consultant traveled 10 hours to attend a meeting. The return trip took only 9 hours because the speed was 8 miles per hour faster. What was the consultants speed each way? No boo

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Question 53099: A consultant traveled 10 hours to attend a meeting. The return trip took only 9 hours because the speed was 8 miles per hour faster. What was the consultants speed each way? No book. Thanks so much for your time!
Found 2 solutions by AnlytcPhil, funmath:
Answer by AnlytcPhil(1807) About Me  (Show Source):
You can put this solution on YOUR website!
A consultant traveled 10 hours to attend a meeting.
The return trip took only 9 hours because the speed 
was 8 miles per hour faster. What was the consultants 
speed each way? No book. Thanks so much for your time!

Make this chart

             DISTANCE     RATE      TIME
Going                                    
Returning                                 

Fill in the times for going and returning,
10 hrs and 9 hrs:

             DISTANCE     RATE      TIME
Going                                 10
Returning                              9

Let x mph be the rate going. Fill that in 

             DISTANCE     RATE      TIME
Going                       x         10
Returning                              9

The speed returning was 8 mph faster than x mph.
So we add 8 mph to x mph and get x+8 mph. So
fill that in as the rate returning


             DISTANCE     RATE      TIME
Going                       x         10
Returning                  x+8         9

Now use D = RT to fill in the distances:

             DISTANCE     RATE      TIME
Going          10x          x         10
Returning     9(x+8)       x+8         9

Now since the distance going was the same as the
distance returning, we set the two distances equal
to each other:

        10x = 9(x+8)

Solve that and get 72 mph going.  Then the rate
returning was 8 mph faster, or 80 mph!  Lucky
he didn't get a speeding ticket! :-)

Edwin

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
distance(d)=rate(r)*time(t)
Trip to the meeting:
time:10
rate:r
distance:10r
-------------
Return Trip:
time:9
rate:r+8
distance:9(r+8)
The distance to the meeting is equal to the return distance, so we can set the two disatnces equal to each other and solve for r.
10r=9(r+8)
10r=9r+72
10r-9r=-9r+9r+72
r=72 mph
The trip to =r=72 mph
Return trip= r+8=72+8=80mph
(They didn't ask, but for fun, you can now find the distance of the trip to be 720 miles. Think about it.)