SOLUTION: My math question is:
Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jorda
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Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jorda
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Question 530936: My math question is:
Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jordan to catch up to Steve?
You can put this solution on YOUR website! Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jordan to catch up to Steve?
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Jordan DATA:
rate = 7 mph ; distance = x miles ; time = x/7 hrs = (60/7)x minutes
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Steve DATA:
rate = 6 mph ; distance = x-5 miles ; time = (x-5)/6 hrs = 10*(x-5) minutes
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Equation:
(60/7)x = 10(x-5)
60x = 70x - 350
10x = 350
x = 35 miles
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Time Jordan needed to catch Steve:
(60/7)x = 60/7 * 35 = 300 minutes = 5 hours
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Quicker method:
At 7 mph Jordan gains 1 mile in 1 hour
So after 5 hours Jordan has caught up with Steve.
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Cheers,
Stan H.
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