SOLUTION: find two consecutive odd integers such that the sum of four times the larger, and 7 more than the smaller is equal to 50

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Question 530862: find two consecutive odd integers such that the sum of four times the larger, and 7 more than the smaller is equal to 50
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Call the numbers n and +n%2B2
given:
+4%2A%28n+%2B+2%29+%2B+n+%2B+7++=+50+
+4n+%2B+8+%2B+n+%2B+7+=+50+
+5n+%2B+15+=+50+
+5n+=+50+-+15+
+5n+=+35+
+n+=+7+
+n+%2B+2+=+9+
The numbers are 7 and 9
check:
+4%2A%287+%2B+2%29+%2B+7+%2B+7++=+50+
+4%2A9+%2B+14+=+50+
+36+%2B+14+=+50+
+50+=+50+
OK