SOLUTION: when the square of three times a positive integer is decreased by the integer, the result is 2010. what is the integer?
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Question 530727: when the square of three times a positive integer is decreased by the integer, the result is 2010. what is the integer? Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! x = a positive integer
3x = 3 times the number
9x^2 = the square of 3 times the number
.
9x^2-x = 2010
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9x^2 -x -2010 = 0
.
Using the quadratic equation, we find:
.