Question 530541: Max is 5 years old than Paul. Next year, Max will be twice as old as Paul. How old are they now? Show equation and check. Found 2 solutions by algebrahouse.com, stanbon:Answer by algebrahouse.com(1659) (Show Source):
You can put this solution on YOUR website! "Max is 5 years old than Paul. Next year, Max will be twice as old as Paul. How old are they now? Show equation and check."
x = Paul's age now
x + 5 = Max's age now
x + 1 = Paul's age next year
x + 6 = Max's age next year
x + 6 = 2(x + 1) {next year, Max will be twice as old as Paul}
x + 6 = 2x + 1 {used distributive property}
6 = x + 1 {subtracted x from both sides}
x = 5 {subtracted 1 from both sides}
x + 5 = 10 {substituted 5, in for x, into x + 5}
You can put this solution on YOUR website! Max is 5 years old than Paul. Next year, Max will be twice as old as Paul. How old are they now? Show equation and check.
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Equations:
m = p+5
m+1 = 2(p+1)
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Substitute for m and solve for "p":
p+5+1 = 2p+2
p+6 = 2p+2
p = 4 yrs (Paul's age now)
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Solve for "m"
m = p+5
m = 4+5 = 9 yrs (Paul's age now)
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Cheers,
Stan H.
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