SOLUTION: Find the center and radius of the circle with the given equation: x^2+y^2-28=0 Thank You : )

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Question 530470: Find the center and radius of the circle with the given equation:
x^2+y^2-28=0
Thank You : )
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2-28=0


x%5E2%2By%5E2=28


%28x-0%29%5E2%2B%28y-0%29%5E2=%28sqrt%2828%29%29%5E2


The equation is now in %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 form, which is a circle, where h=0, k=0 and r=sqrt%2828%29


Remember that the center is (h,k) and the radius is r.


So the center is (0,0) and the radius is sqrt%2828%29 units.


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the center and radius of the circle with the given equation:
x^2+y^2-28=0
----
x^2 + y^2 = 28
---
Center = (0,0)
radius = sqrt(28) = 2sqrt(7)
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Cheers,
Stan H.
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