SOLUTION: Find the factor of: 2a + 7 ----------- a2 - 2a - 15

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Question 530186: Find the factor of:
2a + 7
-----------
a2 - 2a - 15

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
you mean factor a^2 - 2a - 15 ?





Looking at the expression a%5E2-2a-15, we can see that the first coefficient is 1, the second coefficient is -2, and the last term is -15.


Now multiply the first coefficient 1 by the last term -15 to get %281%29%28-15%29=-15.


Now the question is: what two whole numbers multiply to -15 (the previous product) and add to the second coefficient -2?


To find these two numbers, we need to list all of the factors of -15 (the previous product).


Factors of -15:
1,3,5,15
-1,-3,-5,-15


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -15.
1*(-15) = -15
3*(-5) = -15
(-1)*(15) = -15
(-3)*(5) = -15

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -2:


First NumberSecond NumberSum
1-151+(-15)=-14
3-53+(-5)=-2
-115-1+15=14
-35-3+5=2



From the table, we can see that the two numbers 3 and -5 add to -2 (the middle coefficient).


So the two numbers 3 and -5 both multiply to -15 and add to -2


Now replace the middle term -2a with 3a-5a. Remember, 3 and -5 add to -2. So this shows us that 3a-5a=-2a.


a%5E2%2Bhighlight%283a-5a%29-15 Replace the second term -2a with 3a-5a.


%28a%5E2%2B3a%29%2B%28-5a-15%29 Group the terms into two pairs.


a%28a%2B3%29%2B%28-5a-15%29 Factor out the GCF a from the first group.


a%28a%2B3%29-5%28a%2B3%29 Factor out 5 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28a-5%29%28a%2B3%29 Combine like terms. Or factor out the common term a%2B3


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Answer:


So a%5E2-2a-15 factors to %28a-5%29%28a%2B3%29.


In other words, a%5E2-2a-15=%28a-5%29%28a%2B3%29.


Note: you can check the answer by expanding %28a-5%29%28a%2B3%29 to get a%5E2-2a-15 or by graphing the original expression and the answer (the two graphs should be identical).


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Jim