SOLUTION: Find the largest of three consecutive odd integers, such that 3 times the middle integer is 1 more than the sum of the first and third

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Question 530099: Find the largest of three consecutive odd integers, such that 3 times the middle integer is 1 more than the sum of the first and third
Answer by KMST(5328) About Me  (Show Source):
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For 3 consecutive odd integers, the sum of the first and third equals twice the middle one.
The same would be true for 3 consecutive integers, or for 3 consecutive even integers, or ...
Back to the problem.
Let the middle integer be n
We know that 3 times the middle one is 3n
We know that the sum of the largest and smallest is 2n
The problem says that
3n=2n%2B1
That means that n=1, and the 3 consecutive odd integers are
-1, 1, and 3.
The fact that one of them is negative is odd indeed, but -1 is certainly an integer, and I guess it still qualifies as an odd number. It does not divide evenly by 2.