SOLUTION: I've been trying to solve this for a few days and am having no luck and need some help please. f(x)=sqrt x g(x)=x^2 and h(x)= x+2. Write q(x)=sqrt x^2+4x+4 as a composition of f,

We start with

q(x) = 

Since f(x) =  we can write  as f(x²+4x+4)

q(x) = f(x²+4x+4)

We factor the trinomial:

q(x) = f((x+2)(x+2))

We write that product as the square of a binomial:

q(x) = f((x+2)²)

Since g(x)=x², we can write (x+2)² as g(x+2)

q(x) = f(g(x+2))

Since h(x) = x+2, we can write g(x+2) as g(h(x))

q(x) = f(g(h(x)))

and we can write that using the composition notation as

q(x) = f∘(g∘h(x))

And maybe the parentheses can be eliminated and we can just
write

q(x) = f∘g∘h(x)

Edwin