SOLUTION: solve (w+2)^3+88=0 where w is a real number. write your answer in simplified radical form.

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Question 530049: solve (w+2)^3+88=0 where w is a real number. write your answer in simplified radical form.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
solve (w+2)^3+88=0 where w is a real number.
:
(w+2)^3 = -88
Find the cube root of both sides
w + 2 = 3sqrt%28-88%29
factor inside the radical to reveal a perfect cube, -8
w + 2 = 3sqrt%28-8%2A11%29
extract the cube root of -8
w + 2 = -2%2A3sqrt%2811%29
subtract 2 from both sides
w = -2%2A3sqrt%2811%29 - 2