SOLUTION: find a number such that 7 times the number is 56 greater than the opposite
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Question 530011
:
find a number such that 7 times the number is 56 greater than the opposite
Answer by
algebrahouse.com(1659)
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x = the number
7x = -x + 56 {seven times the number is 56 greater than the opposite}
8x = 56 {added x to both sides}
x = 7 {divided both sides by 8}
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