SOLUTION: A tank contains 20 gallons of antifreeze solution. When it is full, it contains 15% antifreeze. How many gallons must be replaced by an 80% antifreeze solution to get 20 gallons

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Question 529835: A tank contains 20 gallons of antifreeze solution. When it is full, it contains 15% antifreeze. How many gallons must be replaced by an 80% antifreeze solution to get 20 gallons of a 70% solution?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = gallons of 15% antifreeze to be
removed and replaced with 80% antifreeze
In words:
( gallons of pure antifreeze at end)/( gallons of solution at end) = 70%
-------------
+.15%2A20+=+3+ gallons of pure antifreeze at start
+20+-+x+ gallons of solution left after removal of x gallons
+.15%2A%28+20+-+x+%29+ = pure antifreeze left after removal of x gallons
+.8x+ = pure antifreeze in 80% solution added
The total gallons of solution has not changed
+%28+.8x+%2B+.15%2A%28+20+-+x+%29+%29+%2F+20+=+.7+
+.8x+%2B+3+-+.15x+=+14+
+.65x+=+11+
+x+=+16.923+
16.923 gallons must be removed and replace with
16.923 gallons of 80% antifreeze
-----------
check:
+20+-+16.923+=+3.077+ gallons of solution left after removal of x gallons
+.15%2A%28+20+-+16.923+%29+=+.4615+ = pure antifreeze left after removal of x gallons
+.8%2A16.923+=+13.538+ = pure antifreeze in 80% solution added
+%28+.8x+%2B+.15%2A%28+20+-+x+%29+%29+%2F+20+=+.7+
+%28+13.538+%2B+.4615+%29+%2F+20+=+.7+
+13.9995+%2F+20+=+.7+
+13.9995+=+14+
error due to rounding off- OK