SOLUTION: When erin and amy went shopping, they stareted with a total of $ 91. amy spent $ 25 and erin spen 3/5 of her money. At that point, amy realized that her remaining money was 3 time

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: When erin and amy went shopping, they stareted with a total of $ 91. amy spent $ 25 and erin spen 3/5 of her money. At that point, amy realized that her remaining money was 3 time      Log On


   



Question 529135: When erin and amy went shopping, they stareted with a total of $ 91. amy spent $ 25 and erin spen 3/5 of her money. At that point, amy realized that her remaining money was 3 times erin's remaining money. how much money did amy have when she started shopping?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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When Erin and Amy went shopping, they started with a total of $91.
Amy spent $25 and Erin spent 3/5 of her money.
At that point, Amy realized that her remaining money was 3 times Erin's remaining money.
how much money did Amy have when she started shopping?
:
let a = amt that Amy had to start
let e = amt that Erin had
:
"they started with a total of $91."
a + e = 91
:
" Amy spent $25 and Erin spent 3/5 of her money. At that point, Amy realized that her remaining money was 3 times Erin's remaining money.
a - 25 = 3(2%2F5e); (she spent 3/5, she has 2/5 remaining)
a - 25 = 6%2F5e
multiply both sides by 5, results:
5(a-25) = 6e
5a - 125 = 6e
5a - 6e = 125
Multiply the 1st equation by 6, add to the above equation
6a + 6e = 546
5a - 6e = 125
---------------adding eliminates e, find a
11a = 671
a = 671%2F11
a = $61 is the amt that Amy started with
:
:
Check this: Erin had 91-61 = 30
a - 25 = 3(2%2F5e)
61 - 25 = 3(2%2F5*30)
36 = 3(12)