SOLUTION: solve the equation on the interval [0,2π] (tanx-1)(cosx+1)=0

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Question 529078: solve the equation on the interval [0,2π]
(tanx-1)(cosx+1)=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve the equation on the interval [0,2π]
(tanx-1)(cosx+1)=0
FOIL
tanxcosx-cosx+tanx-1=0
tanx(cosx+1)-(cosx+1)=0
(cosx+1)(tanx-1)=0
..
cosx+1=0
cosx=-1
x=π
or
tanx-1
x=3π/4 and 7π/4 (reference angle π/4 in quadrants II and IV where tan<1)