+
+ 2x
Write the term 2x as
, so all terms will be fractions:
+
+
The LCD is {x+3)(x-2). We must get all three fractions to have
the LCD for the denominator by multiplying by unit fractions.
The denominator of the first fraction needs to be multiplied by
(x-2) to become the LCD, so we multiply the first fraction by
the unit fraction
The denominator of the second fraction needs to be multiplied by
(x+3) to become the LCD, so we multiply the second fraction by
the unit fraction
The denominator of the third fraction needs to be multiplied by
(x+3)(x-2) to become the LCD, so we multiply the first fraction by
the unit fraction
·
+
·
+
·
+
+
Multiply the tops out but not the bottoms:
+
+
+
+
Since all the deminators are equal to the LCD, we write the sum of the
numerators over the LCD:
Remove the parentheses on top:
Collect like terms in the top and arrange in descending order:
Edwin