SOLUTION: if the hypotenuse of an isosceles triangle is 11 and the angles at the hypotenuse are 45 degrees, how long are the legs?

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Question 528153: if the hypotenuse of an isosceles triangle is 11 and the angles at the hypotenuse are 45 degrees, how long are the legs?
Found 2 solutions by Alan3354, KMST:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
s = leg length
s%5E2+%2B+s%5E2+=+11%5E2
2s%5E2+=+11%5E2
s+=+sqrt%2811%5E2%29%2F2
s+=+11%2Asqrt%282%29%2F2

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Since "hypotenuse" is mentioned, it would be assumed to be a right triangle from the start. Being also isosceles, it is known that it will have two 45 degree angles on the hypotenuse, but it is reassuring that the problem says so.
Being an isosceles right triangle, the length of both legs is the same. Let's call it x
Pythagoras' theorem says that in this case
x%5E2%2Bx%5E2=11%5E2 so
2x%5E2=11%5E2
x%5E2=11%5E2%2F2 and
x=sqrt%2811%5E2%2F2%29=11sqrt%282%29%2F2