SOLUTION: In a normal distribution the mean is 50 and the standard deviation is 5. Find the
proportion of values that do not lie between 48 and 52.
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-> SOLUTION: In a normal distribution the mean is 50 and the standard deviation is 5. Find the
proportion of values that do not lie between 48 and 52.
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Question 528096: In a normal distribution the mean is 50 and the standard deviation is 5. Find the
proportion of values that do not lie between 48 and 52. Answer by reviewermath(1029) (Show Source):
You can put this solution on YOUR website! P(X > 52) = P[Z>(52-50)/5] = P(Z > 0.4)= 0.3446
P(X < 48) = P[Z < (48-50)/5] = P(Z < -0.4) = 0.3446
We add the two probabilities to get the proportion of values that do not lie between 48 and 52, the result is 0.6892.
