Question 527917: solve for x- log3(2x-1)=2+log3(x-2)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! solve for x- log3(2x-1)=2+log3(x-2)
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log3(2x-1)=2+log3(x-2)
log3(2x-1)-log3(x-2)=2
place under single log
log3[(2x-1)/(x-2)]
convert to exponential form: (base(3) raised to log of number(2)=number(2x-1)/(x-2)
3^2=(2x-1)/(x-2)=9
2x-1=9x-18
7x=17
x=17/7
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