SOLUTION: Please help with this!
How do I find the inverse of each function?
1. y= x^2 + 2
2. y= x+2
3. y= 3(x+1)
Thank you so much!
Algebra ->
Rational-functions
-> SOLUTION: Please help with this!
How do I find the inverse of each function?
1. y= x^2 + 2
2. y= x+2
3. y= 3(x+1)
Thank you so much!
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Question 527595: Please help with this!
How do I find the inverse of each function?
1. y= x^2 + 2
2. y= x+2
3. y= 3(x+1)
Thank you so much! Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! How do I find the inverse of each function?
1. y= x^2 + 2
- switch "y for x" and "x for y":
x= y^2 + 2
- solve for y:
x-2= y^2
sqrt(x-2) = y
y = sqrt(x-2)
.
2. y= x+2
- switch "y for x" and "x for y":
x= y+2
- solve for y:
y = x-2
.
3. y= 3(x+1)
- switch "y for x" and "x for y":
x= 3(y+1)
- solve for y:
x= 3(y+1)
x/3= (y+1)
x/3 - 1 = y
y = x/3 - 1
