Question 527436: In mathematics, a word is a list of letters which may or may not form an actual word in English ( or any other language). For example, aa, at, zz, so, ia, and pq are all 2 letter mathematical words. Suppose we wanted to count the total number of 4-letter mathematical words which have no repeating letters.
Which method listed should we use? Combinations, Permutations, n(factor)k, Benford's Law
Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website!
I'm not sure what you mean by "n(factor)k"
I would answer "permutations", for the number of 4-letter
"words" is P(26,4) or on
the TI-84, it's
26 nPr 4
And it is calculated by
26×25×24×23 = 358800
Maybe that's what you mean by n(factor)k. I am not familiar with
"n(factor)k", but maybe you call that "26(factor)4". I'm only familiar
with calling it "The number of permutations of 26 things taken 4 at
a time".
Regardless of what people call it, the number of 4-letter "words"
without repeating letters is:
26×25×24×23 = 358800
Edwin
|
|
|