Question 527323: Determine the quadratic function, f(x)=ax^2+bx+c, whose vertex is (3, 7) and passes through the point (5, -9).
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Determine the quadratic function, f(x)=ax^2+bx+c, whose vertex is (3, 7) and passes through the point (5, -9).
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Second degree equations are parabolas, so write it as a standard form of an equation for a parabola since the vertex is given:
..
y=A(x-h)^2+k=A(x-3)^2+7
Use given point (5,-9) to solve for A
-9=A(5-3)^2+7=4A+7
4A=-16
A=-4
Equation of Parabola: y=-4(x-3)^2+7
=-4(x^2-6x+9)+7=-4x^2+24x-36+7
ans:
f(x)=-4x^2+24x-29
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