SOLUTION: There are (2) questions:
1. Condense the expression to the logarithm of a single quantity: 1/2 ln (2x-1) - 2 ln (x+1)
2. Solve the exponential equation algebraically: 3e^-5x
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-> SOLUTION: There are (2) questions:
1. Condense the expression to the logarithm of a single quantity: 1/2 ln (2x-1) - 2 ln (x+1)
2. Solve the exponential equation algebraically: 3e^-5x
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Question 527313: There are (2) questions:
1. Condense the expression to the logarithm of a single quantity: 1/2 ln (2x-1) - 2 ln (x+1)
2. Solve the exponential equation algebraically: 3e^-5x = 132.
Need help answering these two questions someone please help... Answer by thinkinbig2(5) (Show Source):
You can put this solution on YOUR website! (1)/(2)*ln(2x-1)-2ln(x+1)
Simplify -2ln(x+1) by moving all terms inside the logarithm. The third law of logarithms states that the logarithm of a power of x is equal to the exponent of that power times the logarithm of x (e.g. log^b(x^(n))=nlog^b(x)).
(1)/(2)*ln(2x-1)+ln((x+1)^(-2))
Multiply (1)/(2) by ln(2x-1) to get (ln(2x-1))/(2).
(ln(2x-1))/(2)+ln((x+1)^(-2))
(