SOLUTION: How do you solve for 6x^3=3x^2+3x

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Question 526391: How do you solve for 6x^3=3x^2+3x
Found 2 solutions by jim_thompson5910, oberobic:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!


6x^3=3x^2+3x

6x^3-3x^2-3x=0

3x(2x^2-x-1)=0

3x(x-1)(2x+1)=0

3x=0 or x-1=0 or 2x+1=0

3x=0 or x=1 or 2x=-1

x=0/3 or x=1 or x=-1/2

x=0 or x=1 or x=-1/2


Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
6x^3 = 3x^2 + 3x
6x^3 - 3x^2 -3x = 0
3x*(2x^2 -x -1) = 0
3x*(2x+1)(x-1) = 0
.
x = 0, -1/2, 1
.
+graph%28500%2C500%2C-5%2C5%2C-5%2C5%2C6%2Ax%5E3-3%2Ax%5E2-3%2Ax%29+