Question 526214: A rectangle has a length that is 2ft. longer than its width. if the area is 48ft^2, find its length and width. Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! Area = A = 48 ft^2
Length = l = w+2 ft
Length = ?
Width = ?
Length * Width = Area of Rectangle
l*w=A
(w+2)*(w) = 48
w^2+2w = 48
w^2+2w-48=0
w^2-6w+8w-48=0
w(w-6)+8(w-6)=0
(w-6)(w+8)=0
w-6=0 or w+8=0
w=6 or w=-8 (inadmissble)
so
w=6
Width = 6 ft
Length = l = w+2 = 6+2 = 8 ft
Length is 8 ft
