SOLUTION: Find three consecutive integers such that the first integer plus two times the second integer plus three times the third integer is 98.

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Question 525892: Find three consecutive integers such that the first integer plus two times the second integer plus three times the third integer is 98.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x+2*(x+1)+3*(x+2)=98
x+2x+2+3x+6=98
6x+8=98
6x=90
x=15
x+1=16
x+2=17
check
15+2*16+3*17=98
15+32+51=98
47+51=98
98=98
ok