SOLUTION: I don't know how to solve this i need to verify the identity?
(1+sec(-θ))/(sin(-θ)+tan(-θ))=(1-sec(θ))/(sin(θ)-tan(θ))
Algebra ->
Trigonometry-basics
-> SOLUTION: I don't know how to solve this i need to verify the identity?
(1+sec(-θ))/(sin(-θ)+tan(-θ))=(1-sec(θ))/(sin(θ)-tan(θ))
Log On
Question 525791: I don't know how to solve this i need to verify the identity?
(1+sec(-θ))/(sin(-θ)+tan(-θ))=(1-sec(θ))/(sin(θ)-tan(θ)) Found 2 solutions by Alan3354, lwsshak3:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! You don't solve it.
You determine whether the 2 sides are equal.
---------
Change it all to sines and cosines and simplify it.
You can put this solution on YOUR website! I don't know how to solve this i need to verify the identity?
(1+sec(-θ))/(sin(-θ)+tan(-θ))=(1-sec(θ))/(sin(θ)-tan(θ))
**
sec(-θ)=sec(θ)
sin(-θ)=-sin(θ)
tan(-θ)=-tan(θ)
starting with left side
(1+sec(-θ))/(sin(-θ)+tan(-θ))
[1+sec(θ)]/-sin(θ)-tan(θ)
[1+sec(θ)]/-[sin(θ)+tan(θ)]≠right side
Identity cannot be verified
(