Question 524729: Approximate to the nearest degree, the solutions of the equation in the interval [0°, 360°).
(8cot(x)+1)(cos(x)-4)=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Approximate to the nearest degree, the solutions of the equation in the interval [0°, 360°).
(8cot(x)+1)(cos(x)-4)=0
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8cot(x) = -1 or cos(x) = 4
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cos(x) cannot = 4, so cot(x) = -1/8
x = cot^-1(-1/8) = -82.88 = 277.125 degrees
or x = 277.12-180 = 97.125 degrees
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Cheers,
Stan H.
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