SOLUTION: i am pretty confused, can you help me with solving this problem and show me how its done:
y/(y^2-4^2)- 1/(y-2)
Algebra ->
Rational-functions
-> SOLUTION: i am pretty confused, can you help me with solving this problem and show me how its done:
y/(y^2-4^2)- 1/(y-2)
Log On
Question 524660: i am pretty confused, can you help me with solving this problem and show me how its done:
y/(y^2-4^2)- 1/(y-2) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! y/(y^2-4^2)- 1/(y-2)
---
Factor:
---
[y/(y-4)(y+4)] - [1/(y-2)]
------
least common denominator: (y-2)(y+4)(y-4)
------
Rewrite each fraction with the lcd as its denominator:
[y(y-2)]/lcd - (y-4)(y+4)/lcd
----
Combine the numerators over the lcd
-----
[y^2-2y -[y^2-16]]/lcd
---
= [16-2y]/[(y-2)(y^2-16)]
===========================
Cheers,
Stan H.