SOLUTION: Really stumped on this one!!! A bike is rode 15 miles up a hill and then 15 miles back down the same hill. The total trip takes 2 hours. If the speed going downhill is 20 mph

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Question 524416: Really stumped on this one!!!
A bike is rode 15 miles up a hill and then 15 miles back down the same hill. The total trip takes 2 hours. If the speed going downhill is 20 mph faster than going uphill, how fast is the ride uphill?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You need 2 equations: 1 for uphill and
1 for downhill
d+=+15 mi is the same for both trips
Let t = the time to go uphill in hrs
+2+-+t+ is the speed going downhill in hrs
Let s = the speed going uphill
+s+%2B+20+ is the speed going downhill
----------------------------
Going uphill:
(1) +15+=+s%2At+
Going downhill:
(2) +15+=+%28+s%2B20+%29%2A%28+2-t+%29+
-----------------------
(2) +15+=+2s+%2B+40+-+s%2At+-+20t+
(2) +20t+-+2s+=+25+-+s%2At+
Substitute (1) into (2)
(2) +20t+-+2s+=+25+-+15+
(2) +20t+-+2s+=+10+
-----------------
(1) +15+=+s%2At+
(1) +t+=+15%2Fs+
Substitute this into (2)
(2) +20%2A%2815%2Fs%29+-+2s+=+10+
(2) +300+-+2s%5E2+=+10s+
(2) +2s%5E2+%2B+10s+-+300+=+0+
(2) +s%5E2+%2B+5s+-+150+=+0+
Using the quadratic formula:
s+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
+a+=+1+
+b+=+5+
+c+=+-150+
s+=+%28-5+%2B-+sqrt%28+5%5E2-4%2A1%2A%28-150%29+%29%29%2F%282%2A1%29+
s+=+%28-5+%2B-+sqrt%28+25+%2B+600+%29%29+%2F+2+
s+=+%28-5+%2B-+sqrt%28+625+%29%29+%2F+2+
s+=+%28-5+%2B-+25%29+%2F+2+
+s+=+20%2F2+ ( can't use the negative root )
+s+=+10+
The ride uphill is 10 mi/hr
check:
(1) +15+=+s%2At+
(1) +15+=+10t+
(1) +t+=+1.5+ hrs
and
(2) +15+=+%28+s%2B20+%29%2A%28+2-t+%29+
(2) +15+=+%28+10%2B20+%29%2A%28+2-t+%29+
(2) +15+=+30%2A%28+2-t+%29+
(2) +15+=+60+-+30t+
(2) +30t+=+60+-+15+
(2) +30t+=+45+
(2) +t+=+1.5+ hrs
OK